LearnWave
Learn it. Master it.

Fractions in Disguise

Finding a percentage of a quantity

Learn how to find a percentage of an amount, and why comparing bare percentages can mislead you.

Madhu's biscuits have 25% sugar; Madhav's have 35%. Who ate more sugar?

Careful. A percentage is a share of something, so comparing bare percentages only works if the wholes are the same. If both ate 100 g, Madhav ate 35 g against Madhu's 25 g: easy. But suppose Madhu ate 120 g and Madhav 95 g. Now it has to be worked out.

Madhu: 25% of 120. As a proportion, 25 : 100 :: ? : 120. Or in steps: 25 g of sugar per 100 g of biscuit means 5 g per 20 g, so 30 g per 120 g. Or solve 25/100 = s/120, giving s = (25/100) × 120 = 30 g.

Madhav: 35% of 95. The numbers are less friendly, so go through one gram. 100 g holds 35 g of sugar, so 1 g holds 35/100 g, and 95 g holds (35/100) × 95 = 33.25 g.

So Madhav ate more sugar (33.25 g against 30 g), even though he ate less biscuit. In general, y% of a value is (y/100) × that value. (And x% of y always equals y% of x: 80% of 75 = 75% of 80 = 60. Use whichever is easier.)

A lot of this can be done in your head if you know a few anchors:

%Quick way
50%halve it
25%divide by 4 (25/100 = ¼), so 25% of 40 is 10
10%divide by 10
20%divide by 5

Two relations make the rest easy. First, 20% of a value is double 10% of it, since 20 parts out of 100 is twice 10 parts out of 100. Second, percentages add: (20% of y) + (5% of y) = 25% of y, because (20/100)y + (5/100)y = (25/100)y.

Put those together:

  • 15% = 10% + 5%
  • 40% = 4 × 10%
  • 75% = 50% + 25% (or divide by 4 and multiply by 3)
  • 90% = 100% − 10% (90% of 70 is 70 − 7 = 63)
Find 10%, then build everything else out of it.

Practise this lesson

Questions that get harder as you improve, a Tutor that helps without giving the answer away, and progress you can see. Free for every learner.

No account, no email address. Opens the real product.