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Arithmetic Progressions

AP problems in daily life

Solve everyday problems with the nth term of an AP.

Many real situations grow or shrink by the same amount each step, and that makes them APs. The skill is to spot a (where it starts) and d (the fixed change). Then aₙ = a + (n – 1)d does the rest.

Say in words what each term means. In a garden, a₁ is 'plants in the first row' and a₁₀ is 'plants in the 10th row'.

SituationadQuestion → answer
Simple interest on ₹1000 at 8% (total after each year)8080after 30 years: 80 + 29 × 80 = ₹2400
Rose plants: 23, 21, 19 … 5 in a row23–2how many rows? 5 = 23 + (n – 1)(–2) → 10 rows
Subba Rao's salary: 5000, 5200 …5000200when ₹7000? → 11th year
Ramkali's weekly savings: 5, 6.75, 8.50 …51.75when ₹20.75? → week 10

Simple interest makes an AP because the same interest is added every year. Compound interest does not: it grows by more each year.

When do two APs give the same number? Write both nth terms and set them equal. For 63, 65, 67, … and 3, 10, 17, …: 63 + 2(n – 1) = 3 + 7(n – 1), so 60 = 5(n – 1) and n = 13.

Check your answer makes sense. Rows, weeks and years are whole numbers, and they can't be negative.

In a real problem, find where it starts (a) and the fixed change (d), say what each term means, and use aₙ = a + (n – 1)d.

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