Integrals
Special forms and partial fractions
Integrate quadratic-denominator forms and rational functions.
Six standard forms, all with a square (x² and a²) in the bottom:
- ∫dx/(x² + a²) = (1/a) tan⁻¹(x/a)
- ∫dx/(x² – a²) = (1/2a) log|(x – a)/(x + a)|
- ∫dx/(a² – x²) = (1/2a) log|(a + x)/(a – x)|
- ∫dx/√(a² – x²) = sin⁻¹(x/a)
- ∫dx/√(x² + a²) = log|x + √(x² + a²)|
- ∫dx/√(x² – a²) = log|x + √(x² – a²)|
Add + C to each.
Example: ∫dx/(x² + 9) = (1/3) tan⁻¹(x/3) + C.
If the bottom is a quadratic ax² + bx + c, complete the square to reach one of these. x² + 4x + 13 = (x + 2)² + 9, so ∫dx/(x² + 4x + 13) = (1/3) tan⁻¹((x + 2)/3) + C.
If the top is linear (px + q), write it as A × (derivative of the bottom) + B. The A part gives a log (top = derivative of bottom), and the B part is a standard form.
Partial fractions split a fraction with a factorised bottom into simple fractions you can integrate one by one:
| Bottom has | Write it as |
|---|---|
| (x – a)(x – b) | A/(x – a) + B/(x – b) |
| (x – a)² | A/(x – a) + B/(x – a)² |
| (x – a)(x² + bx + c) | A/(x – a) + (Bx + C)/(x² + bx + c) |
Find A, B by putting convenient values of x. Example: x/((x – 1)(x – 2)) = A/(x – 1) + B/(x – 2). Then x = A(x – 2) + B(x – 1). x = 1 gives A = –1; x = 2 gives B = 2. So the integral is –log|x – 1| + 2 log|x – 2| + C.
This works only for a proper fraction (top degree less than bottom degree). If not, divide first.
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