Measures of Central Tendency
Mean of grouped data; properties; weighted mean
Find the mean of a frequency table and know when it misleads.
For a discrete series (each value with its frequency f), multiply each value by its frequency:
X̄ = ΣfX ÷ Σf
For example, in a survey of families: 10 families have 2 children, 20 have 3, and 10 have 4. ΣfX = 20 + 60 + 40 = 120, and Σf = 40, so the mean is 120 ÷ 40 = 3 children.
For a continuous series (data in classes), we do not know the exact values in each class, so each class is represented by its mid-point, m:
X̄ = Σfm ÷ Σf
The assumed mean and step deviation methods work here too, using the mid-points, and give the same result. Remember: if the classes are inclusive (10-19, 20-29…), the mid-points can still be found directly, but check that classes are set out correctly before you start.
Two properties of the arithmetic mean:
- The sum of the deviations of the values from their mean is always zero: Σ(X – X̄) = 0. The values above the mean exactly balance those below it.
- The mean is affected by extreme values. If one or two students from a college get very high packages while most get modest ones, the mean package looks much better than what most students actually receive. For the values 3, 5, 7 and 85, the mean is 25, although three of the four values are below 10.
Sometimes items are not equally important. A weighted mean gives each item a weight (w) to show its importance:
Weighted mean = Σwx ÷ Σw
For example, to find the average price change in a family's shopping, a rise in the price of rice (a big part of the budget) should count more than a rise in the price of salt.
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