Dividing by place value

In your book, Maths Mela (Chapter 9), Sunitha's mother has 62 candies to share equally among 5 children. She divides using place value. 62 is 6 Tens and 2 Ones. First share the Tens: 6 Tens ÷ 5 = 1 Ten each, with 1 Ten left over. Regroup that 1 Ten into 10 Ones. Now there are 10 + 2 = 12 Ones. 12 Ones ÷ 5 = 2 Ones each, with 2 left over. So each child gets 1 Ten and 2 Ones = 12 candies, and the remainder is 2.

Next, 324 ÷ 3. 324 is 3 Hundreds, 2 Tens and 4 Ones. 3 Hundreds ÷ 3 = 1 Hundred each. 2 Tens cannot be shared among 3 without regrouping, so everyone gets 0 Tens, and we must write that 0 in the Tens place of the quotient. Regroup the 2 Tens into 20 Ones: 20 + 4 = 24 Ones. 24 Ones ÷ 3 = 8 Ones. So 324 ÷ 3 = 108, not 18.

For 136 ÷ 6, 1 Hundred cannot be shared among 6, so regroup it into 10 Tens. That makes 13 Tens. 13 Tens ÷ 6 = 2 Tens each, with 1 Ten left. Regroup it: 10 + 6 = 16 Ones. 16 Ones ÷ 6 = 2 Ones each, with 4 left. So 136 ÷ 6 = 22, remainder 4. Because the Hundreds could not be shared, the quotient has only 2 digits.

Four-digit numbers work the same way. For 3,005 ÷ 5: 3 Thousands cannot be shared among 5, so regroup them into 30 Hundreds. 30 Hundreds ÷ 5 = 6 Hundreds. There are 0 Tens, so the Tens place of the quotient gets 0. 5 Ones ÷ 5 = 1. So 3,005 ÷ 5 = 601. Always put the 0 in the right place!